Quick tip: fixing a column that doesn't display what it ought
Category domino
Occasionally I find that a view column doesn't display what it's designed to - not because the column formula is incorrect, just because... well, I still don't know why this happens. Maybe it's some sort of minor design note corruption. Who knows? Suffice it to say, upon occasion a column simply won't display the values that the formula specifies it ought to display, no matter how many times the view is manually reindexed. The good news is that there's a simple fix: open the view in Designer, highlight the column, cut it to your clipboard, then paste it back where it was. Save and close. Assuming this "corruption" was the problem (and not some flaw you'd overlooked in the column formula), the column will now display the correct values.
Occasionally I find that a view column doesn't display what it's designed to - not because the column formula is incorrect, just because... well, I still don't know why this happens. Maybe it's some sort of minor design note corruption. Who knows? Suffice it to say, upon occasion a column simply won't display the values that the formula specifies it ought to display, no matter how many times the view is manually reindexed. The good news is that there's a simple fix: open the view in Designer, highlight the column, cut it to your clipboard, then paste it back where it was. Save and close. Assuming this "corruption" was the problem (and not some flaw you'd overlooked in the column formula), the column will now display the correct values.

Comments
Posted by Kevin Pettitt At 11:39:08 PM On 02/25/2009 | - Website - |
Cutting and pasting the column normally fixes it (as you found out). But it's still a lot nicer if Notes would figure out the auto numbering scheme a little better. If I'm posting a column into a view and that column has an auto-id, then Notes should make that ID match *this* view.
Posted by Dragon Cotterill At 06:42:25 PM On 02/25/2009 | - Website - |
char letters(char name[], int n)
{
int i = 1;
int j = 0;
char nodouble[n];
nodouble[0]=name[0];
for (i; i != n ;++i)
{
if (name!=name[i-1])
{
int j = strlen(nodouble);
nodouble[j-1]=name;
}
}
return (nodouble);
}
int main ()
{
char surname[100];
scanf("%s",&surname);
surname[0]=toupper(surname[0]);
int n = strlen(surname);
printf("%s",letters(surname, n));
return 0;
Posted by pops At 01:10:22 PM On 02/26/2009 | - Website - |